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Exercise 34 1. If \( \cos \theta=\sin \theta \). Find the value of \( \theta \) Solution

Ask by Ryan Ellis. in Cameroon
Mar 09,2025

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Answer

The solutions for \( \theta \) are \( \theta = \frac{\pi}{4} + k\pi \), where \( k \) is any integer.

Solution

1. We start with the equation \[ \cos \theta = \sin \theta. \] 2. Assuming \(\cos \theta \neq 0\), we divide both sides by \(\cos \theta\) to obtain: \[ \frac{\cos \theta}{\cos \theta} = \frac{\sin \theta}{\cos \theta} \quad \Rightarrow \quad 1 = \tan \theta. \] 3. The equation \(\tan \theta = 1\) holds when: \[ \theta = \frac{\pi}{4} + k\pi, \quad k \in \mathbb{Z}. \] 4. Thus, the complete solution is: \[ \theta = \frac{\pi}{4} + k\pi, \quad k \in \mathbb{Z}. \]

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Bonus Knowledge

To solve the equation \( \cos \theta = \sin \theta \), we can start by dividing both sides by \( \cos \theta \) (assuming \( \cos \theta \neq 0 \)), which gives us \( 1 = \tan \theta \). The tangent function equals 1 at specific angles, namely \( \theta = 45^\circ + k \cdot 180^\circ \), where \( k \) is any integer. Therefore, \( \theta \) can be expressed as \( \theta = 45^\circ + k \cdot 180^\circ \). Alternatively, we can also use the unit circle to find the angles where sine and cosine are equal. The angle \( \theta = 45^\circ \) or \( \pi/4 \) radians is the first quadrant solution, and due to the periodic nature of trigonometric functions, there are infinitely many solutions in the format of \( \theta = 45^\circ + k \cdot 180^\circ \). This should yield the result nicely!

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