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34. Dadas las funciones \( f(x)=x^{2}, g(x)=\frac{1}{3} x^{2} y h(x)=3 x^{2} \). ¿Cuál de las siguientes opciones es correcta? A) \( f\left(\frac{1}{3}\right)
Ask by Smith Gray. in Chile
Mar 17,2025

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Answer

La opción correcta es B: \( g\left(\frac{1}{3}\right) < f\left(\frac{1}{3}\right) < h\left(\frac{1}{3}\right) \).

Solution

Para \( x=\frac{1}{3} \) evaluamos cada función: 1. Para \( f(x)=x^{2} \): \[ f\left(\frac{1}{3}\right)=\left(\frac{1}{3}\right)^{2}=\frac{1}{9} \] 2. Para \( g(x)=\frac{1}{3}x^{2} \): \[ g\left(\frac{1}{3}\right)=\frac{1}{3}\left(\frac{1}{3}\right)^{2}=\frac{1}{3}\cdot\frac{1}{9}=\frac{1}{27} \] 3. Para \( h(x)=3x^{2} \): \[ h\left(\frac{1}{3}\right)=3\left(\frac{1}{3}\right)^{2}=3\cdot\frac{1}{9}=\frac{3}{9}=\frac{1}{3} \] Comparando los valores obtenidos: \[ \frac{1}{27} < \frac{1}{9} < \frac{1}{3} \] correspondiendo a \( g\left(\frac{1}{3}\right) < f\left(\frac{1}{3}\right) < h\left(\frac{1}{3}\right) \). Por lo tanto, la opción correcta es la opción B.

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Primero, evaluamos las funciones en \( x = \frac{1}{3} \): - \( f\left(\frac{1}{3}\right) = \left(\frac{1}{3}\right)^{2} = \frac{1}{9} \) - \( g\left(\frac{1}{3}\right) = \frac{1}{3} \left(\frac{1}{3}\right)^{2} = \frac{1}{3} \cdot \frac{1}{9} = \frac{1}{27} \) - \( h\left(\frac{1}{3}\right) = 3 \left(\frac{1}{3}\right)^{2} = 3 \cdot \frac{1}{9} = \frac{1}{3} \) Ahora, comparamos los resultados: - \( g\left(\frac{1}{3}\right) = \frac{1}{27} \) - \( f\left(\frac{1}{3}\right) = \frac{1}{9} \) - \( h\left(\frac{1}{3}\right) = \frac{1}{3} \) Dado que \( g\left(\frac{1}{3}\right) < f\left(\frac{1}{3}\right) < h\left(\frac{1}{3}\right) \), la opción correcta es B. ¡Y ahí lo tienes, un pequeño juego de funciones que resulta en una emocionante competencia!

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