Find the indicated probability using the standard normal distribution. \( P(-3.04

Ask by Rogers Fleming. in the United States

Feb 18,2025

We need to find P(–3.04 < z < 3.04). Because the standard normal distribution is symmetric about 0, we can use the property:   P(–a < z < a) = 2Φ(a) – 1 Here, a = 3.04, so we have:   P(–3.04 < z < 3.04) = 2Φ(3.04) – 1 Using the standard normal table for z = 3.04, we find that:   Φ(3.04) ≈ 0.9988 Now substitute this value:   P(–3.04 < z < 3.04) = 2(0.9988) – 1 = 1.9976 – 1 = 0.9976 Rounded to four decimal places, the probability is 0.9976.