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Home \( > \) CC2 \( > \) Chapter \( 6> \) Lesson \( 6.2 .3> \) Problem 6-81 Solve each equation below for \( x \). Check your final answer. \( \begin{array}{ll}\text { a. } 4 x=6 x-14 & \text { b. } 3 x+5=50 \\ \boxtimes \square \operatorname{step} 1 \text { (a): }\end{array} \)

Ask by Adkins Perkins. in the United States
Feb 28,2025

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Answer

Solutions: (a) \( x = 7 \) (b) \( x = 15 \)

Solution

Below are the steps to solve each equation and check your final answer. ───────────────────────────── Part (a): Solve 4x = 6x – 14 Step 1: Get all x terms on one side. Subtract 6x from both sides:   4x – 6x = 6x – 14 – 6x   –2x = –14 Step 2: Isolate x by dividing both sides by –2:   x = (–14)/(–2)   x = 7 Step 3: Check your answer by substituting x = 7 into the original equation:   Left side: 4(7) = 28   Right side: 6(7) – 14 = 42 – 14 = 28   Since 28 = 28, the solution x = 7 is correct. ───────────────────────────── Part (b): Solve 3x + 5 = 50 Step 1: Isolate the x term by subtracting 5 from both sides:   3x + 5 – 5 = 50 – 5   3x = 45 Step 2: Divide both sides by 3:   x = 45/3   x = 15 Step 3: Check your answer:   Substitute x = 15 into the original equation:   3(15) + 5 = 45 + 5 = 50   Since 50 = 50, the solution x = 15 is verified. ───────────────────────────── Final Answers: (a) x = 7 (b) x = 15

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Let's solve the first equation step by step and then tackle the second one! For equation (a) \( 4x = 6x - 14 \): Step 1: Start by isolating \( x \). Subtract \( 6x \) from both sides: \[ 4x - 6x = -14 \] This simplifies to: \[ -2x = -14 \] Step 2: Now, divide both sides by -2: \[ x = 7 \] To check, substitute \( x = 7 \) back into the original equation: \[ 4(7) = 6(7) - 14 \] This gives: \[ 28 = 42 - 14 \] Which simplifies to: \[ 28 = 28 \] (True!) Now, for equation (b) \( 3x + 5 = 50 \): Step 1: Isolate \( 3x \) by subtracting 5 from both sides: \[ 3x = 50 - 5 \] This simplifies to: \[ 3x = 45 \] Step 2: Now, divide both sides by 3: \[ x = 15 \] Check this by substituting \( x = 15 \): \[ 3(15) + 5 = 50 \] This gives: \[ 45 + 5 = 50 \] Which simplifies to: \[ 50 = 50 \] (True!) So, the solutions are \( x = 7 \) for (a) and \( x = 15 \) for (b). Happy solving!

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