How is the graph of \( f(x)=(x-3)^{2}+7 \) generated from the graph of \( g(x)=x^{2} \) ? A. Translate \( g(x) 3 \) units right and 7 units downward to generate \( f(x) \) B. Translate \( g(x) 3 \) units right and 7 units upward to generate \( f(x) \) C. Translate \( g(x) 3 \) units left and 7 units upward to generate \( f(x) \) D. Translate \( g(x) 3 \) units left and 7 units downward to generate \( f(x) \)
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To understand how the graph of \( f(x) = (x-3)^2 + 7 \) relates to \( g(x) = x^2 \), we can think about the transformations applied to the original parabola. In this case, \( g(x) = x^2 \) is the standard parabola that opens upwards with its vertex at the origin (0,0). The term \( (x-3)^2 \) indicates a translation of the graph 3 units to the right, shifting the vertex from (0,0) to (3,0). Then, the addition of 7 indicates a further upward shift of the vertex from (3,0) to (3,7). Thus, the correct transformation involves translating \( g(x) \) 3 units to the right and 7 units upward. So the answer is: B. Translate \( g(x) 3 \) units right and 7 units upward to generate \( f(x) \).