Find the number of ordinates if the equal width of subintervals for \( \int_{0}^{2} x^{2} \sin x d x \) is 0.4 .

To find the number of ordinates (subintervals) for the integral \( \int_{0}^{2} x^{2} \sin x \, dx \) given that the width of each subinterval is \( 0.4 \), we can follow these steps: 1. **Calculate the total interval length**: The limits of integration are from \( 0 \) to \( 2 \), so the total length of the interval is: \[ L = 2 - 0 = 2. \] 2. **Determine the width of each subinterval**: Given that the width \( w \) of each subinterval is \( 0.4 \). 3. **Calculate the number of subintervals (ordinates)**: The number of subintervals \( n \) can be found by dividing the total length of the interval by the width of each subinterval: \[ n = \frac{L}{w} = \frac{2}{0.4} = 5. \] Thus, the number of ordinates is \( 5 \).