Use the properties of logarithms to expand the following expression as much as possible. Simplify any numerical expressions that can be evaluated. without a calculator. \[ \ln \left(\frac{x^{8} \sqrt{p^{7} q^{3}}}{e^{9}}\right) \]
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First, we can apply the logarithmic property for the quotient, which states that \(\ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b)\). Thus, we write: \[ \ln \left(\frac{x^{8} \sqrt{p^{7} q^{3}}}{e^{9}}\right) = \ln(x^{8} \sqrt{p^{7} q^{3}}) - \ln(e^{9}). \] Next, we can simplify \(\ln(e^{9})\) using the property \(\ln(e^a) = a\): \[ \ln(e^{9}) = 9. \] Now, for the first term \(\ln(x^{8} \sqrt{p^{7} q^{3}})\), we can further apply the product property, \(\ln(ab) = \ln(a) + \ln(b)\): \[ \ln(x^{8} \sqrt{p^{7} q^{3}}) = \ln(x^{8}) + \ln(\sqrt{p^{7} q^{3}}). \] For \(\ln(x^{8})\), we can use \(\ln(a^b) = b \ln(a)\): \[ \ln(x^{8}) = 8 \ln(x). \] Now, for the square root term, recall that \(\sqrt{a} = a^{1/2}\): \[ \ln(\sqrt{p^{7} q^{3}}) = \ln((p^{7} q^{3})^{1/2}) = \frac{1}{2} \ln(p^{7} q^{3}). \] Applying the product property again: \[ \ln(p^{7} q^{3}) = \ln(p^{7}) + \ln(q^{3}) = 7 \ln(p) + 3 \ln(q). \] Putting this all together: \[ \ln \left(\frac{x^{8} \sqrt{p^{7} q^{3}}}{e^{9}}\right) = \left(8 \ln(x) + \frac{1}{2}(7 \ln(p) + 3 \ln(q))\right) - 9. \] Distributing the \(\frac{1}{2}\): \[ = 8 \ln(x) + \frac{7}{2} \ln(p) + \frac{3}{2} \ln(q) - 9. \] Therefore, the fully expanded expression is: \[ \ln \left(\frac{x^{8} \sqrt{p^{7} q^{3}}}{e^{9}}\right) = 8 \ln(x) + \frac{7}{2} \ln(p) + \frac{3}{2} \ln(q) - 9. \]