\( \begin{array}{l}\text { Discuss the continuity of } \\ \text { the function at } x=1\end{array} f(x)=\left\{\left.\begin{array}{ll}3 x-1 & \text { if } x<1 \\ 4 & \text { if } x=1 \\ 2 x & \text { if } x>1\end{array} \right\rvert\,\right. \)
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To determine the continuity of the function \( f(x) \) at \( x=1 \), we first need to check three conditions: the function must be defined at \( x=1 \), the limit as \( x \) approaches 1 must exist, and the limit must equal the function's value at that point. In this case, \( f(1) = 4 \). The limit from the left, as \( x \) approaches 1, is \( 3(1) - 1 = 2 \). The limit from the right is \( 2(1) = 2 \). Since both one-sided limits equal 2 and are not equal to \( f(1) = 4 \), the function is not continuous at \( x=1 \). This example illustrates a classic case of a jump discontinuity—where the function leaps from one value to another without connecting through the intermediate values. Understanding continuity is crucial not just in calculus but also in various fields like physics and engineering, where processes often rely on smoothly functioning systems. It’s a great reminder to verify what happens at points where functions seem to change state!