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What value of \( t \) is a solution to this equation? \( -3 t+6 t-1=-1 \) \( t=0 \) \( t=2 \)

Ask by Campos Schofield. in the United States
Jan 10,2025

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\( t = 0 \)

Solution

To solve the equation: \[ -3t + 6t - 1 = -1 \] **Step 1: Simplify the equation** Combine like terms on the left side: \[ (-3t + 6t) - 1 = 3t - 1 \] So the equation becomes: \[ 3t - 1 = -1 \] **Step 2: Solve for \( t \)** Add 1 to both sides of the equation: \[ 3t - 1 + 1 = -1 + 1 \] \[ 3t = 0 \] Now, divide both sides by 3: \[ t = \frac{0}{3} = 0 \] **Conclusion:** The solution to the equation is: \[ t = 0 \] Therefore, among the given options, \( t = 0 \) is the correct solution. **Answer:** \( t = 0 \)

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Mind Expander

To solve the equation \( -3t + 6t - 1 = -1 \), first combine like terms on the left side: \[ (6t - 3t) - 1 = -1 \] \[ 3t - 1 = -1 \] Next, add 1 to both sides: \[ 3t = 0 \] Now, divide by 3 to isolate \( t \): \[ t = 0 \] So \( t = 0 \) is indeed a solution to the equation! But hold on! Let's double check if \( t = 2 \) would work too. If we substitute \( t = 2 \) into our equation: \[ -3(2) + 6(2) - 1 = -1 \] \[ -6 + 12 - 1 = -1 \] \[ 5 \neq -1 \] So it's confirmed, only \( t = 0 \) fits the bill! 🎉

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