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A roller coaster has 10 carts that will seat up to 3 people each. If 24 people are seated in the carts ant NO carts are empty, what is the greatest possible number of carts that could be filled with 3 people? A. 4 B. 5 C. 6 D. 7

Ask by Hall John. in the United States
Feb 26,2025

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Answer

The greatest number of carts that can be filled with 3 people is 7.

Solution

To solve the problem, we need to determine how many carts can be filled with 3 people while ensuring that all 10 carts are used and a total of 24 people are seated. 1. **Identify the total seating capacity**: Each cart can seat 3 people, and there are 10 carts. Therefore, the total seating capacity is: \[ \text{Total capacity} = 10 \text{ carts} \times 3 \text{ people/cart} = 30 \text{ people} \] 2. **Determine the number of people seated**: We know that 24 people are seated in the carts. 3. **Calculate the number of empty seats**: Since the total capacity is 30 and 24 people are seated, the number of empty seats is: \[ \text{Empty seats} = 30 - 24 = 6 \text{ seats} \] 4. **Determine the number of carts filled with 3 people**: If we want to maximize the number of carts filled with 3 people, we need to minimize the number of carts that have fewer than 3 people. Let \( x \) be the number of carts filled with 3 people. The number of people seated in these carts is: \[ 3x \] The remaining people seated in the other carts (which must have at least 1 person each) can be expressed as: \[ 24 - 3x \] The number of carts that are not filled with 3 people is: \[ 10 - x \] Since each of these remaining carts must have at least 1 person, we have: \[ 24 - 3x \geq 10 - x \] 5. **Solve the inequality**: Rearranging the inequality gives: \[ 24 - 3x + x \geq 10 \] \[ 24 - 2x \geq 10 \] \[ 14 \geq 2x \] \[ 7 \geq x \] This means that the maximum number of carts that can be filled with 3 people is 7. 6. **Check if 7 carts can be filled**: If \( x = 7 \): - People in 7 carts: \( 3 \times 7 = 21 \) - Remaining people: \( 24 - 21 = 3 \) - Carts left: \( 10 - 7 = 3 \) - Each of the remaining 3 carts can have 1 person, which satisfies the condition. Thus, the greatest possible number of carts that could be filled with 3 people is \( \boxed{7} \).

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To maximize the number of carts filled with 3 people, we should first calculate how many people would fill the maximum number of carts. If we fill x carts with 3 people and the remaining carts with 1 person each, the equation would look like this: 3x + (10 - x) = 24. Simplifying gives us 2x = 14, thus x = 7. Since not all carts can be filled with 3 people, we can only fill 6 carts with 3 (18 people) and one cart with 6 people (24 in total). Hence the greatest number of carts that can be filled with 3 people is 6 (Option C). To clarify, how we lay out people in the carts can affect the outcome when filling carts. It's crucial to remember that even if you fill one cart less, its contribution still plays a role in the total equation, so managing those numbers carefully leads to the right solution!

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