(1) \( x+1=b(b-x) \) \( \begin{array}{ll}\text { (3) } 4 a x-4 b x=a^{2}-2 a b+b^{2} & \text { (4) } \frac{x^{2}}{c^{2}}=b^{2} \\ \text { (5) } \frac{x}{a}-3=5-\frac{x}{b} & \text { (6) } \frac{x+a}{x-b}=\frac{c}{3} \\ \text { (7) } \frac{a}{x-1}=\frac{b}{x+2} & \text { (8) } \frac{2 x}{x+a}=\frac{b}{x-1}+2 \\ \text { (g) } \text { Los op vir } x \text { en stel jou antwoord op 'n getallelyn voor: } \\ \text { (1) } 2 x+1 \geq 13 & \text { (2) } 2-2 x \leq 3 \\ \text { (3) } 3(x+7)>6 & \text { (4) } 10-2 x<22+2 x \\ \text { (5) } \frac{1-x}{2} \leq 3-x & \text { (6) } \frac{-5 x}{3}-1 \geq x+7 \\ \text { Los op vir } x \text { en stel jou antwoord op 'n getallelyn voor: } \\ \text { (1) }-4 \leq-2 x<6 & \text { (2) }-8 \leq 4 x-12<0 \\ \text { (3) }-7 \leq 3 x-1<5 & \text { (4) }-2 \leq 4-2 x \leq 8 \\ \text { (5) }-4<\frac{3 x-5}{2}<8 & \text { (6) }-5<\frac{1-2 x}{3} \leq 3\end{array} \)
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