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Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits. \[ \begin{array}{l}78.08 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 70 \mathrm{~L}=\square \mathrm{mol} \\ 542.0 \mathrm{~mol}+66.611 \mathrm{~L}=\square \frac{\mathrm{mol}}{\mathrm{L}} \\ 7.808 \frac{\mathrm{~g}}{\mathrm{~mL}} \times 3.65 \mathrm{~mL}=\square \mathrm{g}\end{array} \]

Ask by Santiago Bond. in the United States
Feb 26,2025

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Answer

Here are the answers with the correct number of significant digits: 1. \( 78.08 \, \frac{\text{mol}}{\text{L}} \times 70 \, \text{L} = 5.5 \times 10^3 \, \text{mol} \) 2. \( 542.0 \, \text{mol} \div 66.611 \, \text{L} \approx 8.132 \, \frac{\text{mol}}{\text{L}} \) 3. \( 7.808 \, \frac{\text{g}}{\text{mL}} \times 3.65 \, \text{mL} = 28.5 \, \text{g} \)

Solution

Below is one way to work through the problem. (Note: In the second expression the unit of the answer is mol/L—which is what you get for concentration (moles divided by volume). Although a plus sign is shown, the proper operation there is division.) 1) Multiply 78.08 mol/L by 70 L.   Calculation:    78.08 mol/L × 70 L = 5465.6 mol   Now for significant figures: 78.08 has 4 significant figures. For the “70 L” the number of significant figures is ambiguous because it is not written in scientific notation; we assume it has 2 significant figures. When multiplying, the answer must have the same number of significant figures as the factor with the fewest. Therefore the answer must have 2 significant figures.   Rounding 5465.6 mol to 2 significant figures gives 5.5×10³ mol. 2) Divide 542.0 mol by 66.611 L to get the concentration in mol/L.   Calculation:    542.0 mol ÷ 66.611 L ≈ 8.132 mol/L   Now for significant figures: 542.0 has 4 significant figures and 66.611 has 5 significant figures. The result should have 4 significant figures (the smaller count). Thus, 8.132 mol/L is the answer (you might also round to 8.13 mol/L if preferred, but 8.132 already shows 4 significant digits). 3) Multiply 7.808 g/mL by 3.65 mL.   Calculation:    7.808 g/mL × 3.65 mL = 28.4992 g   Now for significant figures: 7.808 has 4 significant figures and 3.65 has 3 significant figures. The answer must be given with 3 significant figures.   Rounding 28.4992 g to 3 significant figures gives 28.5 g. To summarize, the answers (with the proper significant digit treatment) are:   • 78.08 mol/L × 70 L = 5.5×10³ mol   • 542.0 mol ÷ 66.611 L ≈ 8.132 mol/L   • 7.808 g/mL × 3.65 mL = 28.5 g

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The Deep Dive

To solve the given problems while following the rules of significant digits: 1. For the multiplication \( 78.08 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 70 \mathrm{~L} \): - \( 78.08 \) has 4 significant figures, and \( 70 \) has 2 significant figures. - The result is \( 78.08 \times 70 = 5465.6 \), but we must round to 2 significant figures: \( 5500 \mathrm{~mol} \). 2. For the addition \( 542.0 \mathrm{~mol} + 66.611 \mathrm{~L} \): - Here, we should clarify units. Assuming the intent is to add both as \( \mathrm{~mol} \), the relevant measurement is \( 542.0 \) (4 significant figures) and \( 66.611 \) (5 significant figures) in the same unit. You need to round the result to the smallest decimal place. - The result is \( 542.0 + 66.611 = 608.611 \), rounded to \( 608.6 \mathrm{~mol} \). 3. For the multiplication \( 7.808 \frac{\mathrm{~g}}{\mathrm{~mL}} \times 3.65 \mathrm{~mL} \): - \( 7.808 \) has 4 significant figures and \( 3.65 \) has 3 significant figures. - The result of the multiplication is \( 7.808 \times 3.65 = 28.5052 \), but should be rounded to 3 significant figures: \( 28.5 \mathrm{~g} \). So the final answers are: \[ \begin{array}{l} 78.08 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 70 \mathrm{~L} = 5500 \mathrm{~mol} \\ 542.0 \mathrm{~mol} + 66.611 \mathrm{~mol} = 608.6 \mathrm{~mol} \\ 7.808 \frac{\mathrm{~g}}{\mathrm{~mL}} \times 3.65 \mathrm{~mL} = 28.5 \mathrm{~g} \end{array} \]

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Chemistry Colombia Feb 26, 2025
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