Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits. \[ \begin{array}{l}78.08 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 70 \mathrm{~L}=\square \mathrm{mol} \\ 542.0 \mathrm{~mol}+66.611 \mathrm{~L}=\square \frac{\mathrm{mol}}{\mathrm{L}} \\ 7.808 \frac{\mathrm{~g}}{\mathrm{~mL}} \times 3.65 \mathrm{~mL}=\square \mathrm{g}\end{array} \]
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The Deep Dive
To solve the given problems while following the rules of significant digits: 1. For the multiplication \( 78.08 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 70 \mathrm{~L} \): - \( 78.08 \) has 4 significant figures, and \( 70 \) has 2 significant figures. - The result is \( 78.08 \times 70 = 5465.6 \), but we must round to 2 significant figures: \( 5500 \mathrm{~mol} \). 2. For the addition \( 542.0 \mathrm{~mol} + 66.611 \mathrm{~L} \): - Here, we should clarify units. Assuming the intent is to add both as \( \mathrm{~mol} \), the relevant measurement is \( 542.0 \) (4 significant figures) and \( 66.611 \) (5 significant figures) in the same unit. You need to round the result to the smallest decimal place. - The result is \( 542.0 + 66.611 = 608.611 \), rounded to \( 608.6 \mathrm{~mol} \). 3. For the multiplication \( 7.808 \frac{\mathrm{~g}}{\mathrm{~mL}} \times 3.65 \mathrm{~mL} \): - \( 7.808 \) has 4 significant figures and \( 3.65 \) has 3 significant figures. - The result of the multiplication is \( 7.808 \times 3.65 = 28.5052 \), but should be rounded to 3 significant figures: \( 28.5 \mathrm{~g} \). So the final answers are: \[ \begin{array}{l} 78.08 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 70 \mathrm{~L} = 5500 \mathrm{~mol} \\ 542.0 \mathrm{~mol} + 66.611 \mathrm{~mol} = 608.6 \mathrm{~mol} \\ 7.808 \frac{\mathrm{~g}}{\mathrm{~mL}} \times 3.65 \mathrm{~mL} = 28.5 \mathrm{~g} \end{array} \]