tactorize \( m^{3}+n^{3} \) \( a^{1 x}-b^{6} \) \( 8 x^{3}-y^{9} \) \( x^{3}+8 y^{3} \)

Factor the expression by following steps: - step0: Factor: \(m^{3}+n^{3}\) - step1: Factor the expression: \(\left(m+n\right)\left(m^{2}-mn+n^{2}\right)\) Factor the expression \( x^{3}+8 y^{3} \). Factor the expression by following steps: - step0: Factor: \(x^{3}+8y^{3}\) - step1: Rewrite the expression: \(x^{3}+\left(2y\right)^{3}\) - step2: Factor the expression: \(\left(x+2y\right)\left(x^{2}-x\times 2y+\left(2y\right)^{2}\right)\) - step3: Calculate: \(\left(x+2y\right)\left(x^{2}-2xy+4y^{2}\right)\) Factor the expression \( 8 x^{3}-y^{9} \). Factor the expression by following steps: - step0: Factor: \(8x^{3}-y^{9}\) - step1: Rewrite the expression: \(\left(2x\right)^{3}-y^{9}\) - step2: Factor the expression: \(\left(2x-y^{3}\right)\left(\left(2x\right)^{2}+2xy^{3}+y^{6}\right)\) - step3: Evaluate: \(\left(2x-y^{3}\right)\left(4x^{2}+2xy^{3}+y^{6}\right)\) Here are the factorizations for the given expressions: 1. **For \( m^{3}+n^{3} \)**: \[ m^{3}+n^{3} = (m+n)(m^{2}-mn+n^{2}) \] 2. **For \( a^{1 x}-b^{6} \)**: - Unfortunately, no result could be found for this expression. It seems there might be a typo or an unconventional format in the expression. Please check the expression and provide a corrected version. 3. **For \( 8 x^{3}-y^{9} \)**: \[ 8 x^{3}-y^{9} = (2x-y^{3})(4x^{2}+2xy^{3}+y^{6}) \] 4. **For \( x^{3}+8 y^{3} \)**: \[ x^{3}+8 y^{3} = (x+2y)(x^{2}-2xy+4y^{2}) \] If you have any further questions or need additional assistance, feel free to ask!