14. [-/1 Points] DETAILS MY NOTES Find $$ f^{\prime}(a) $$. $$ f(x)=4 x^{2}-5 x+3 $$ $$ f^{\prime}(a)=\square $$

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1. Given the function  
   $$
   f(x)=4x^2-5x+3,
   $$  
   we differentiate it with respect to $$ x $$.

2. Compute the derivative term-by-term:  
   $$
   f'(x)=\frac{d}{dx}(4x^2)-\frac{d}{dx}(5x)+\frac{d}{dx}(3).
   $$

3. Differentiate each term:  
   - For $$ 4x^2 $$:  
     $$
     \frac{d}{dx}(4x^2)=4\cdot 2x=8x.
     $$
   - For $$ -5x $$:  
     $$
     \frac{d}{dx}(-5x)=-5.
     $$
   - For the constant $$ 3 $$:  
     $$
     \frac{d}{dx}(3)=0.
     $$

4. Combine the results:  
   $$
   f'(x)=8x-5.
   $$

5. To find $$ f'(a) $$, simply substitute $$ x=a $$:  
   $$
   f'(a)=8a-5.
   $$
$$ f'(a) = 8a - 5 $$

14. [-/1 Points] DETAILS MY NOTES Find \( f^{\prime}(a) \). \( f(x)=4 x^{2}-5 x+3 \) \( f^{\prime}(a)=\square \)

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