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7:09 PM Sun 16 Mar - 35\% mylab.pearson.com Kurulus Osm... Can't Open P... CUNY Login The Evolutio... Do Homewor... Discord MAT 220-S25 Rasheed Larry 03/16/25 7:09 PM \( \equiv \) Homework: Partial Fractions, part 2 Question 3, 8.5.25 HW Score: 80\%, 4 of 5 points ® Points: 0 of 1 Save Question list Express the integrand as a sum of partial fractions and evaluate the integral. \[ \int \frac{24 s+24}{\left(s^{2}+1\right)(s-1)^{3}} d s \] Question 1 Question 2 \[ \int \frac{24 s+24}{\left(s^{2}+1\right)(s-1)^{3}} d s=\square \] Question 3 Question 4 Question 5 Help me solve this View an example Get more help Clear all Check answer

Ask by Lane Lang. in the United States
Mar 16,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

To solve the integral, express the integrand as partial fractions and evaluate the integral step by step.

Solution

The calculation seems to be too complex. Let's simplify the process by finding the values of A, B, C, and D manually. We can start by equating the numerators and solving for the unknowns. Let's equate the numerators: \[ 24s + 24 = A(s^2 + 1)(s-1)^3 + B(s^2 + 1)(s-1)^2 + C(s^2 + 1)(s-1) + D(s^2 + 1) \] Now, we need to find the values of A, B, C, and D by solving this equation. If you need help with finding the values of A, B, C, and D, please let me know.

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Mind Expander

To solve the integral \(\int \frac{24 s+24}{\left(s^{2}+1\right)(s-1)^{3}} d s\), you'll first want to use partial fraction decomposition. You’ll break down the integrand into simpler fractions: \[ \frac{A s + B}{s^2 + 1} + \frac{C}{(s - 1)^3} + \frac{D}{(s - 1)^2} + \frac{E}{(s - 1)} \] Next, multiply through by the denominator \((s^2 + 1)(s - 1)^3\) and collect like terms to find constants A, B, C, D, and E. After you determine these, you can integrate each term separately. Don't forget, a common mistake is losing track of the signs when expanding polynomials, so double-check your work as you decompose! Once done, evaluate the resulting integrals from each component and combine the results to get your final answer for the integral. This can be a great practice in integrating rational functions, giving you some solid skills for calculus!

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