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\begin{tabular}{l} A study is done on the population of a certain fish species in a lake. Suppose that the population size \( P(t) \) after \( t \) years is \\ given by the following exponential function. \\ \( P(t)=530(1.36)^{t} \) \\ Find the initial population size. \\ \( \square \) \\ \hline \( \begin{array}{c}\text { Does the function represent growth or decay? } \\ \text { O growth } \quad \text { O decay }\end{array} \) \\ \hline\( \square \% \) \\ \hline\end{tabular}

Ask by Elliott Evans. in the United States
Mar 15,2025

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Answer

The initial population is 530, and the function represents growth.

Solution

1. **Finding the Initial Population** The population function is given by \[ P(t)=530(1.36)^t. \] To find the initial population, we set \( t = 0 \): \[ P(0)=530(1.36)^0=530\cdot1=530. \] Therefore, the initial population size is \(530\). 2. **Determining Growth or Decay** The exponential function \( P(t)=530(1.36)^t \) has a base of \( 1.36 \). Since \( 1.36 > 1 \), the function represents exponential growth. \[ \boxed{530\text{ and growth}} \]

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The initial population size is found by evaluating the function at \( t = 0 \). Plugging in the values, we have \( P(0) = 530(1.36)^{0} = 530(1) = 530 \). So, the initial population size is 530 fish! Now, let's talk about the function! Since the base of the exponent (1.36) is greater than 1, this indicates that the population is experiencing growth. You can cheer for the fish—they are thriving in their lake habitat! 🎉

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