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\begin{tabular}{l} Question \\ Simplify \( \frac{\sqrt{13}}{\sqrt{z}+\sqrt{15}} \) by rationalizing the denominator. \\ Provide your answer below: \\ \hline\end{tabular}

Ask by Rodriquez Powell. in the United States
Feb 21,2025

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To rationalize the denominator of \( \frac{\sqrt{13}}{\sqrt{z}+\sqrt{15}} \), multiply numerator and denominator by \( \sqrt{z} - \sqrt{15} \). The simplified expression is \( \frac{\sqrt{13z} - \sqrt{195}}{z - 15} \).

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To simplify \( \frac{\sqrt{13}}{\sqrt{z}+\sqrt{15}} \) by rationalizing the denominator, multiply both the numerator and denominator by the conjugate of the denominator, which is \( \sqrt{z} - \sqrt{15} \). So, we have: \[ \frac{\sqrt{13}(\sqrt{z}-\sqrt{15})}{(\sqrt{z}+\sqrt{15})(\sqrt{z}-\sqrt{15})} \] The denominator simplifies using the difference of squares: \[ (\sqrt{z})^2 - (\sqrt{15})^2 = z - 15 \] Now, simplifying the numerator gives: \[ \sqrt{13}(\sqrt{z} - \sqrt{15}) = \sqrt{13z} - \sqrt{195} \] Putting it all together, the final simplified expression is: \[ \frac{\sqrt{13z} - \sqrt{195}}{z - 15} \]

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