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Found each fraction to 0, \( \frac{1}{2} \), or 1. Use a number line if needed. \( \begin{array}{lll}\text { 1. } \frac{5}{9} \approx & \text { 2. } \frac{1}{14} \approx & \text { 3. } \frac{12}{13} \approx \\ \text { 4. } \frac{2}{13} \approx & \text { 5. } \frac{9}{11} \approx & \text { 6. } \frac{9}{17} \approx \frac{1}{2}\end{array} \)

Ask by Hamilton Wade. in the United States
Feb 21,2025

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\[ \begin{array}{lll} 1. \frac{5}{9} \approx \frac{1}{2} & 2. \frac{1}{14} \approx 0 & 3. \frac{12}{13} \approx 1 \\ 4. \frac{2}{13} \approx 0 & 5. \frac{9}{11} \approx 1 & 6. \frac{9}{17} \approx \frac{1}{2} \end{array} \]

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To find the approximate values for these fractions, let's consider their positions between 0 and 1. 1. \( \frac{5}{9} \) is about 0.56, closer to 1/2, so it’s approximately 1. 2. \( \frac{1}{14} \) is quite small, much closer to 0, so it’s approximately 0. 3. \( \frac{12}{13} \) is very close to 1 since it's just 1 part away from the whole, so it’s approximately 1. 4. \( \frac{2}{13} \) is still small, even though it's more than \( \frac{1}{14} \), so it's approximately 0. 5. \( \frac{9}{11} \) is quite close to 1, since it’s nearly a whole, so it’s approximately 1. 6. \( \frac{9}{17} \) is slightly less than 1/2 since 9 is less than half of 17; therefore, it's approximately 0. So the approximations are: 1. 1 2. 0 3. 1 4. 0 5. 1 6. 0.

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