10) \( 1 \frac{3}{8}-\left(\frac{7}{3}-\frac{1}{12}\right)= \)

To solve the expression \( 1 \frac{3}{8} - \left(\frac{7}{3} - \frac{1}{12}\right) \), we first convert the mixed number \( 1 \frac{3}{8} \) into an improper fraction. This becomes \( \frac{11}{8} \). Now we need to simplify the parentheses: To subtract, we need a common denominator for \( \frac{7}{3} \) and \( \frac{1}{12} \). The least common multiple of 3 and 12 is 12. So, we convert \( \frac{7}{3} \) to \( \frac{28}{12} \) and keep \( \frac{1}{12} \) as it is. Now, we calculate: \[ \frac{28}{12} - \frac{1}{12} = \frac{27}{12} \] Now we substitute back into the original equation: \[ \frac{11}{8} - \frac{27}{12} \] Next, we find a common denominator between 8 and 12, which is 24. We convert both fractions: \[ \frac{11}{8} = \frac{33}{24} \] \[ \frac{27}{12} = \frac{54}{24} \] Now, we can subtract: \[ \frac{33}{24} - \frac{54}{24} = \frac{-21}{24} = -\frac{7}{8} \] Thus, the final answer is: \[ -\frac{7}{8} \]