2.6 If one bus can transport 36 tourists, how many buses are needed to transport 175 tourists? 2.7 A car travels at a speed of \( 110 \mathrm{~km} / \mathrm{h} \). How far will the car travel in 7,25 hours. 2.8 The petrol consumption of cars is \( 18 \mathrm{k} / 1 \). How many liters of petrol are needed to travel 490 km ? 2.9 Pamela saved up to buy a camera that was priced at R 3 600 . Every month she saved the same amount. After five months she had saved the money, but the camera price had increased by \( 12 \% \). \( 2.9 .1 \quad \) How much did Pamela save every month? 2.9 .2 Calculate the increased price of the camera. \( 2.9 .3 \quad \) How many months will she takes to save the balance of the money (2) required to buy the camera.

**2.6 Calculation of the number of buses** - One bus can carry \(36\) tourists. - To transport \(175\) tourists, we need at least \[ \frac{175}{36} \approx 4.8611 \] - Since we cannot use a fraction of a bus, we round up to the nearest whole number. - **Answer:** \(5\) buses. **2.7 Distance travelled by the car** - The car travels at a speed of \(110 \, \mathrm{km/h}\). - Time travelled is \(7.25\) hours. - Using the formula \[ \text{Distance} = \text{Speed} \times \text{Time}, \] we have \[ 110 \times 7.25 = 797.5 \, \mathrm{km}. \] - **Answer:** The car travels \(797.5 \, \mathrm{km}\). **2.8 Petrol needed for the trip** - The car consumes \(18 \, \mathrm{km}\) per litre of petrol. - To travel \(490 \, \mathrm{km}\), the liters required are \[ \frac{490}{18} \approx 27.22 \, \text{litres}. \] - **Answer:** Approximately \(27.22\) litres of petrol are needed. **2.9 Pamela’s savings for the camera** *2.9.1 Monthly saving amount* - The initial camera price was \(R3600\). - Pamela saved the same amount every month and managed to save \(R3600\) in \(5\) months. - Monthly saving is \[ \frac{3600}{5} = 720. \] - **Answer:** Pamela saved \(R720\) every month. *2.9.2 Increased camera price* - The camera price increased by \(12\%\). - The increased price is calculated by \[ 3600 \times 1.12 = 4032. \] - **Answer:** The new price of the camera is \(R4032\). *2.9.3 Additional months required to save the balance* - Total amount needed now is \(R4032\). - Already saved in \(5\) months is \(R3600\). - The remaining balance is \[ 4032 - 3600 = 432. \] - With a monthly saving of \(R720\), the additional time needed is \[ \frac{432}{720} = 0.6 \, \text{month}. \] - Since savings are made on a monthly basis, Pamela will need to save for **1 extra month** to cover the balance. - **Answer:** It will take an additional \(1\) month to save the remaining money.