2.6 If one bus can transport 36 tourists, how many buses are needed to transport 175 tourists? 2.7 A car travels at a speed of $$ 110 \mathrm{~km} / \mathrm{h} $$. How far will the car travel in 7,25 hours. 2.8 The petrol consumption of cars is $$ 18 \mathrm{k} / 1 $$. How many liters of petrol are needed to travel 490 km ? 2.9 Pamela saved up to buy a camera that was priced at R 3 600 . Every month she saved the same amount. After five months she had saved the money, but the camera price had increased by $$ 12 \% $$. $$ 2.9 .1 \quad $$ How much did Pamela save every month? 2.9 .2 Calculate the increased price of the camera. $$ 2.9 .3 \quad $$ How many months will she takes to save the balance of the money (2) required to buy the camera.

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**2.6 Calculation of the number of buses**  
- One bus can carry $$36$$ tourists.  
- To transport $$175$$ tourists, we need at least  
  $$
  \frac{175}{36} \approx 4.8611
  $$
- Since we cannot use a fraction of a bus, we round up to the nearest whole number.  
- **Answer:** $$5$$ buses.

**2.7 Distance travelled by the car**  
- The car travels at a speed of $$110 \, \mathrm{km/h}$$.  
- Time travelled is $$7.25$$ hours.  
- Using the formula  
  $$
  \text{Distance} = \text{Speed} \times \text{Time},
  $$
  we have  
  $$
  110 \times 7.25 = 797.5 \, \mathrm{km}.
  $$
- **Answer:** The car travels $$797.5 \, \mathrm{km}$$.

**2.8 Petrol needed for the trip**  
- The car consumes $$18 \, \mathrm{km}$$ per litre of petrol.  
- To travel $$490 \, \mathrm{km}$$, the liters required are  
  $$
  \frac{490}{18} \approx 27.22 \, \text{litres}.
  $$
- **Answer:** Approximately $$27.22$$ litres of petrol are needed.

**2.9 Pamela’s savings for the camera**

*2.9.1 Monthly saving amount*  
- The initial camera price was $$R3600$$.  
- Pamela saved the same amount every month and managed to save $$R3600$$ in $$5$$ months.  
- Monthly saving is  
  $$
  \frac{3600}{5} = 720.
  $$
- **Answer:** Pamela saved $$R720$$ every month.

*2.9.2 Increased camera price*  
- The camera price increased by $$12\%$$.  
- The increased price is calculated by  
  $$
  3600 \times 1.12 = 4032.
  $$
- **Answer:** The new price of the camera is $$R4032$$.

*2.9.3 Additional months required to save the balance*  
- Total amount needed now is $$R4032$$.  
- Already saved in $$5$$ months is $$R3600$$.  
- The remaining balance is  
  $$
  4032 - 3600 = 432.
  $$
- With a monthly saving of $$R720$$, the additional time needed is  
  $$
  \frac{432}{720} = 0.6 \, \text{month}.
  $$
- Since savings are made on a monthly basis, Pamela will need to save for **1 extra month** to cover the balance.
- **Answer:** It will take an additional $$1$$ month to save the remaining money.
**2.6** - **Answer:** 5 buses are needed. **2.7** - **Answer:** The car travels 797.5 km. **2.8** - **Answer:** Approximately 27.22 litres of petrol are needed. **2.9.1** - **Answer:** Pamela saved R720 every month. **2.9.2** - **Answer:** The camera now costs R4032. **2.9.3** - **Answer:** Pamela needs 1 more month to save the remaining money.

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