Question

21) \( 35 x^{3}-28 x^{2}-20 x+10 \)

Ask by Hall Hanson. in the United States
Mar 12,2025

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The expression \( 35 x^{3}-28 x^{2}-20 x+10 \) can be factored as \( 5(7 x^{3}-4 x^{2}-4 x+2) \). The cubic polynomial \( 7 x^{3}-4 x^{2}-4 x+2 \) does not factor nicely with rational coefficients.

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Beyond the Answer

To start, let's look at factoring. The polynomial \( 35x^{3}-28x^{2}-20x+10 \) can be simplified by factoring out a common factor first. In this case, we notice that 5 is a common factor for all terms. Factoring that out gives us: \[ 5(7x^{3}-\frac{28}{5}x^{2}-4x+2) \] Now, if you want to get more advanced, you might use synthetic division or the Rational Root Theorem to find possible rational roots and then factor further. Additionally, substituting values can help find roots, making the polynomial easier to work with or solve. For instance, trying \( x = 1 \), \( 7(1)^{3} - \frac{28}{5}(1)^{2} - 4(1) + 2 \) can tell us if \( x = 1 \) is a root, paving the way for polynomial long division to simplify further.

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