Question
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\( \frac { 5 a ^ { 2 x } - 10 a ^ { x } + 1 } { a ^ { 2 } - 2 a } \)

Ask by Graham Moran. in South Africa
Mar 13,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The expression cannot be simplified further without specific values for \(a\) and \(x\).

Solution

Simplify the expression by following steps: - step0: Solution: \(\frac{\left(5a^{2x}-10a^{x}+1\right)}{\left(a^{2}-2a\right)}\) - step1: Remove the parentheses: \(\frac{5a^{2x}-10a^{x}+1}{a^{2}-2a}\) The expression you provided is \[ \frac{5a^{2x} - 10a^{x} + 1}{a^{2} - 2a} \] Upon simplification, it remains as \[ \frac{5a^{2x} - 10a^{x} + 1}{a^{2} - 2a} \] This indicates that the expression cannot be simplified further without specific values for \(a\) and \(x\). If you have any specific values or further operations in mind, please let me know!

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Simplify this solution

Bonus Knowledge

To simplify the expression \( \frac { 5 a ^ { 2 x } - 10 a ^ { x } + 1 } { a ^ { 2 } - 2 a } \), we can start by factoring both the numerator and the denominator. The denominator can be factored as: \[ a^2 - 2a = a(a - 2) \] Next, we will focus on the numerator \( 5 a^{2x} - 10 a^x + 1 \). This resembles a quadratic in terms of \( a^x \). We can rewrite it as: \[ 5 (a^x)^2 - 10 (a^x) + 1 \] Now, let's set \( y = a^x \). The expression now becomes: \[ 5y^2 - 10y + 1 \] We can factor this quadratic: \[ 5y^2 - 10y + 1 = (5y - 1)(y - 1) \] using the quadratic formula or by inspection. Substituting back \( y = a^x \), we have: \[ (5a^x - 1)(a^x - 1) \] So, the entire expression simplifies to: \[ \frac{(5a^x - 1)(a^x - 1)}{a(a - 2)} \] You can further analyze this expression for specific values of \( a \) and \( x \) if needed.

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