Question $$ 1(1 $$ point) $$ \checkmark $$ soved Translate from exponential form to logarithmic form. $$ 3^{3}=27 $$ $$ \log _{27}(3)=3 $$ $$ \log _{3}(3)=27 $$ $$ \log _{3}=\frac{3}{27} $$ $$ \log _{3}(27)=3 $$

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To translate the exponential form $$ 3^{3} = 27 $$ into logarithmic form, we follow the definition of logarithms. The general form of the logarithm is:

$$
b^y = x \quad \text{is equivalent to} \quad \log_b(x) = y
$$

In this case, we have:

- $$ b = 3 $$
- $$ y = 3 $$
- $$ x = 27 $$

Thus, we can write:

$$
\log_{3}(27) = 3
$$

Now, let's evaluate the options provided:

1. $$ \log_{27}(3) = 3 $$ - Incorrect.
2. $$ \log_{3}(3) = 27 $$ - Incorrect.
3. $$ \log_{3} = \frac{3}{27} $$ - Incorrect.
4. $$ \log_{3}(27) = 3 $$ - Correct.

The correct translation from exponential form to logarithmic form is:

$$
\log_{3}(27) = 3
$$

So, the answer is option 4: $$ \log_{3}(27) = 3 $$.
$$ \log_{3}(27) = 3 $$

Question \( 1(1 \) point) \( \checkmark \) soved Translate from exponential form to logarithmic form. \( 3^{3}=27 \) \( \log _{27}(3)=3 \) \( \log _{3}(3)=27 \) \( \log _{3}=\frac{3}{27} \) \( \log _{3}(27)=3 \)

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