\( \begin{array}{l}4 x+2 y=12 \\ -4 x-5 y=6\end{array} \) What is the solution \( (x, y) \) to the given system of equations? Choose 1 answer:
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To solve the system of equations, let's start with the first equation: 1. From the first equation \(4x + 2y = 12\), we can simplify it to \(2x + y = 6\) by dividing the whole equation by 2. 2. Now let's solve for \(y\): \(y = 6 - 2x\). 3. Substitute \(y\) into the second equation \(-4x - 5y = 6\): \(-4x - 5(6 - 2x) = 6\). 4. Simplifying that, we get: \(-4x - 30 + 10x = 6\), \(6x - 30 = 6\), \(6x = 36\), \(x = 6\). 5. Now substitute \(x = 6\) back into \(y = 6 - 2x\): \(y = 6 - 2(6) = 6 - 12 = -6\). So the solution to the system of equations is \((6, -6)\).