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Decide whether the function is one-to-one. \( y=\frac{-3}{x+9} \) Is the function one-to-one? Yes No

Ask by Ross Pierce. in the United States
Feb 28,2025

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Answer

The function is one-to-one.

Solution

A function is one-to-one if every element in the range corresponds to exactly one element in the domain. One way to test this is to assume that f(a) = f(b) and then show that a must equal b. For the function f(x) = -3/(x + 9), assume that:   -3/(a + 9) = -3/(b + 9) Multiply both sides by (a + 9)(b + 9) (which we can do as long as a and b are not -9):   -3(b + 9) = -3(a + 9) Divide both sides by -3:   b + 9 = a + 9 Subtract 9 from both sides:   b = a Since f(a) = f(b) implies that a = b, the function is one-to-one. Thus, the answer is: Yes.

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To determine if the function \( y=\frac{-3}{x+9} \) is one-to-one, we can use the horizontal line test. A function is one-to-one if every horizontal line intersects the graph at most once. For this rational function, as \( x \) approaches negative infinity, \( y \) approaches 0, and as \( x \) approaches negative 9, \( y \) approaches negative infinity. Because the function is always decreasing and passes the horizontal line test, it is indeed one-to-one! Another way to check if a function is one-to-one is by calculating its derivative. If the derivative does not change sign (i.e., is always positive or always negative), then the function is one-to-one. For this function, the derivative is negative, confirming the function is decreasing throughout its domain, further solidifying that it is one-to-one.

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