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To simplify \( \frac{2}{\sqrt{5}-5} \), we can rationalize the denominator by multiplying the numerator and the denominator by the conjugate of the denominator, which is \( \sqrt{5}+5 \). This gives us: \[ \frac{2(\sqrt{5}+5)}{(\sqrt{5}-5)(\sqrt{5}+5)} = \frac{2(\sqrt{5}+5)}{5 - 25} = \frac{2(\sqrt{5}+5)}{-20} = -\frac{\sqrt{5}+5}{10} \] So, the simplified form is \( -\frac{\sqrt{5}+5}{10} \). To double-check, remember the property of conjugates: \( (a - b)(a + b) = a^2 - b^2 \), which in our case confirms that the denominator becomes \( 5 - 25 = -20 \). If you ever find a complex denominator, multiplying by its conjugate is a nifty trick to make it manageable!