Question
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8) \( \frac{2}{\sqrt{5}-5} \)

Ask by Wilson Weaver. in the United States
Mar 11,2025

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Tutor-Verified Answer

Answer

\[ -\frac{\sqrt{5}+5}{10} \]

Solution

We start with the expression \[ \frac{2}{\sqrt{5}-5}. \] **Step 1: Multiply by the conjugate** Multiply the numerator and the denominator by the conjugate of the denominator, which is \(\sqrt{5}+5\): \[ \frac{2}{\sqrt{5}-5} \cdot \frac{\sqrt{5}+5}{\sqrt{5}+5}. \] **Step 2: Simplify the expression** The numerator becomes \[ 2(\sqrt{5}+5). \] The denominator is the difference of two squares: \[ (\sqrt{5}-5)(\sqrt{5}+5) = (\sqrt{5})^2 - 5^2 = 5 - 25 = -20. \] Thus, the expression becomes: \[ \frac{2(\sqrt{5}+5)}{-20}. \] **Step 3: Reduce the fraction** Factor \(2\) out of the numerator and simplify with \(-20\): \[ \frac{2(\sqrt{5}+5)}{-20} = \frac{\sqrt{5}+5}{-10} = -\frac{\sqrt{5}+5}{10}. \] The simplified form is \[ -\frac{\sqrt{5}+5}{10}. \]

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Mind Expander

To simplify \( \frac{2}{\sqrt{5}-5} \), we can rationalize the denominator by multiplying the numerator and the denominator by the conjugate of the denominator, which is \( \sqrt{5}+5 \). This gives us: \[ \frac{2(\sqrt{5}+5)}{(\sqrt{5}-5)(\sqrt{5}+5)} = \frac{2(\sqrt{5}+5)}{5 - 25} = \frac{2(\sqrt{5}+5)}{-20} = -\frac{\sqrt{5}+5}{10} \] So, the simplified form is \( -\frac{\sqrt{5}+5}{10} \). To double-check, remember the property of conjugates: \( (a - b)(a + b) = a^2 - b^2 \), which in our case confirms that the denominator becomes \( 5 - 25 = -20 \). If you ever find a complex denominator, multiplying by its conjugate is a nifty trick to make it manageable!

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