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\( \left. \begin{array} { l } { 9 x + 8 = 4 x + 23 } \\ \hline 6 ( x - 2 ) = 3 x + 9 \\ { 3 x - 5 = x + 11 } \\ { 7 x - 2 = 3 x + 14 } \\ { 9 x + 7 = 2 ( 4 x + 5 ) } \\ \hline \end{array} \right. \)

Ask by Cole Clark. in Mexico
Mar 13,2025

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Answer

Las soluciones son: 1. \( x = 3 \) 2. \( x = 7 \) 3. \( x = 8 \) 4. \( x = 4 \) 5. \( x = 3 \)

Solution

1. Resolver \(9x+8=4x+23\): - Restamos \(4x\) a ambos lados: \[ 9x - 4x + 8 = 23 \quad \Rightarrow \quad 5x + 8 = 23 \] - Restamos 8 a ambos lados: \[ 5x = 23 - 8 \quad \Rightarrow \quad 5x = 15 \] - Dividimos entre 5: \[ x = \frac{15}{5} \quad \Rightarrow \quad x = 3 \] 2. Resolver \(6(x-2)=3x+9\): - Aplicamos la propiedad distributiva: \[ 6x - 12 = 3x + 9 \] - Restamos \(3x\) a ambos lados: \[ 6x - 3x - 12 = 9 \quad \Rightarrow \quad 3x - 12 = 9 \] - Sumamos 12 a ambos lados: \[ 3x = 9 + 12 \quad \Rightarrow \quad 3x = 21 \] - Dividimos entre 3: \[ x = \frac{21}{3} \quad \Rightarrow \quad x = 7 \] 3. Resolver \(3x-5=x+11\): - Restamos \(x\) a ambos lados: \[ 3x - x - 5 = 11 \quad \Rightarrow \quad 2x - 5 = 11 \] - Sumamos 5 a ambos lados: \[ 2x = 11 + 5 \quad \Rightarrow \quad 2x = 16 \] - Dividimos entre 2: \[ x = \frac{16}{2} \quad \Rightarrow \quad x = 8 \] 4. Resolver \(7x-2=3x+14\): - Restamos \(3x\) a ambos lados: \[ 7x - 3x - 2 = 14 \quad \Rightarrow \quad 4x - 2 = 14 \] - Sumamos 2 a ambos lados: \[ 4x = 14 + 2 \quad \Rightarrow \quad 4x = 16 \] - Dividimos entre 4: \[ x = \frac{16}{4} \quad \Rightarrow \quad x = 4 \] 5. Resolver \(9x+7=2(4x+5)\): - Aplicamos la propiedad distributiva en el lado derecho: \[ 9x + 7 = 8x + 10 \] - Restamos \(8x\) a ambos lados: \[ 9x - 8x + 7 = 10 \quad \Rightarrow \quad x + 7 = 10 \] - Restamos 7 a ambos lados: \[ x = 10 - 7 \quad \Rightarrow \quad x = 3 \]

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The Deep Dive

To solve the system of equations: 1. **9x + 8 = 4x + 23**: Rearranging gives us \(9x - 4x = 23 - 8\), leading to \(5x = 15\), so \(x = 3\). 2. **6(x - 2) = 3x + 9**: Expanding gives \(6x - 12 = 3x + 9\). Rearranging results in \(6x - 3x = 9 + 12\) or \(3x = 21\), hence \(x = 7\). 3. **3x - 5 = x + 11**: Rearranging gives \(3x - x = 11 + 5\), resulting in \(2x = 16\) which simplifies to \(x = 8\). 4. **7x - 2 = 3x + 14**: Rearranging results in \(7x - 3x = 14 + 2\), or \(4x = 16\), thus \(x = 4\). 5. **9x + 7 = 2(4x + 5)**: Expanding gives us \(9x + 7 = 8x + 10\). Rearranging results in \(9x - 8x = 10 - 7\) or \(x = 3\). Now to summarize the solutions from all equations: 1. \(x = 3\) 2. \(x = 7\) 3. \(x = 8\) 4. \(x = 4\) 5. \(x = 3\) The solutions demonstrate that different equations yield different values for \(x\). When working with equations, it's often beneficial to recheck your operations to avoid common pitfalls like misplacing terms or mixing up equals. Double-check each step to maintain clarity in your solution process! For a deeper dive, consider "Algebra" by Israel M. Gelfand & Alexander Shen, which presents fun approaches to linear equations. Another engaging read is "The Art of Problem Solving" series; it’s chock-full of strategies that can make tackling algebra a thrilling journey!

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