Question
Laisha is responsible for bringing the desserts to a friend's birthday party. * 2 points She is buying a cake for \( \$ 25.00 \) and also cupcakes for \( \$ 1.25 \) each. If she has budgeted \( \$ 60 \) total, what is the maximum number of cupcakes she can buy? A. 68 cupcakes B. 48 cupcakes C. 28 cupcakes D. 20 cupcakes
Ask by Parry Davies. in the United States
Mar 11,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
Laisha can buy a maximum of 28 cupcakes.
Solution
1. Let \( x \) be the number of cupcakes Laisha can buy.
2. The total cost for the cupcakes is \( 1.25x \). Including the cake, the total expense is
\[
25 + 1.25x.
\]
3. Setting up the inequality under her budget of \( \$60 \), we have
\[
25 + 1.25x \leq 60.
\]
4. Subtract \( 25 \) from both sides:
\[
1.25x \leq 35.
\]
5. Divide both sides by \( 1.25 \):
\[
x \leq \frac{35}{1.25} = 28.
\]
6. Since \( x \) must be an integer, the maximum number of cupcakes she can buy is \( 28 \).
Answer: C. 28 cupcakes.
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Simplify this solution Extra Insights
To figure out the maximum number of cupcakes Laisha can buy, we first need to subtract the cost of the cake from her total budget. The cake costs \$25.00, so: \[ \$60.00 - \$25.00 = \$35.00 \] Now, we can determine how many cupcakes she can buy with the remaining budget. Since each cupcake costs \$1.25, we divide the remaining budget by the cost of one cupcake: \[ \frac{\$35.00}{\$1.25} = 28 \] Thus, the maximum number of cupcakes Laisha can buy is **C. 28 cupcakes**.
