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Consider the following scenario: A sample of radioactive material has a decay constant of 0.02 per day. If there are initially 20 grams of the material, what formula would you use to determine how much will remain after 10 days? ( 1 point) \( y=10(0.98)^{20} \) \( y=20(0.02)^{10} \) \( y=20(0.98)^{10} \) \( y=10(0.02)^{20} \)

Ask by Mcguire Colon. in the United States
Mar 14,2025

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The formula to determine the remaining amount after 10 days is \( y = 20(0.98)^{10} \).

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To figure out how much radioactive material is left after 10 days, you would use the exponential decay formula: \( y = y_0 e^{-\lambda t} \), where \( y_0 \) is the initial amount, \( \lambda \) is the decay constant, and \( t \) is time. In this case, you would convert it to the form \( y = y_0 (1 - \lambda)^t \), making it \( y = 20(0.98)^{10} \). The correct answer clearly here is \( y = 20(0.98)^{10} \)! This means that after 10 days, you'll see a little less radioactive material than what you started with. It's a bit like watching your ice cream melt on a hot day – it just keeps fading away!

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