In how many ways could members of the following club line up all 8 members for a photograph? $$ \mathrm{N}=\{ $$ Bob, Tim, Alan, Tammy, Cathy, David, Sandy, Ashley $$ \} $$ $$ \square $$ way(s) (Simplify your answer.)

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1. We need to determine in how many distinct orders 8 members can line up. This is a permutation problem.

2. The total number of ways to arrange $$ 8 $$ distinct members is given by $$ 8! $$ (8 factorial).

3. Calculating $$ 8! $$:
   $$
   8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 40320
   $$

4. Therefore, the members can line up in $$ 40320 $$ different ways.
There are 40,320 different ways for the 8 members to line up.

In how many ways could members of the following club line up all 8 members for a photograph? \( \mathrm{N}=\{ \) Bob, Tim, Alan, Tammy, Cathy, David, Sandy, Ashley \( \} \) \( \square \) way(s) (Simplify your answer.)

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