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5. Simplify. \( \begin{array}{ll}\text { a) }\left(x^{4}\right)^{5} & \text { b) }\left(3 x^{2}\right)^{3} \\ \text { c) } 4(57 a b)^{0} & \text { d) }\left(\frac{y^{11}}{y^{3}}\right)^{2}\end{array} \)

Ask by Cruz Macdonald. in South Africa
Feb 20,2025

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Tutor-Verified Answer

Answer

a) \( x^{20} \) b) \( 27x^{6} \) c) \( 4 \) d) \( y^{16} \)

Solution

Simplify the expression by following steps: - step0: Solution: \(\left(x^{4}\right)^{5}\) - step1: Multiply the exponents: \(x^{4\times 5}\) - step2: Multiply the numbers: \(x^{20}\) Calculate or simplify the expression \( (3 x^{2})^{3} \). Simplify the expression by following steps: - step0: Solution: \(\left(3x^{2}\right)^{3}\) - step1: Use the properties of exponents: \(3^{3}\left(x^{2}\right)^{3}\) - step2: Evaluate the power: \(27x^{6}\) Calculate or simplify the expression \( (y^{11}/y^{3})^{2} \). Simplify the expression by following steps: - step0: Solution: \(\left(\frac{y^{11}}{y^{3}}\right)^{2}\) - step1: Divide the terms: \(\left(y^{8}\right)^{2}\) - step2: Transform the expression: \(y^{8\times 2}\) - step3: Multiply the numbers: \(y^{16}\) Calculate or simplify the expression \( 4(57 a b)^{0} \). Simplify the expression by following steps: - step0: Solution: \(4\left(57ab\right)^{0}\) - step1: Rewrite the expression: \(4\times 1\) - step2: Multiply: \(4\) Here are the simplified results for each part: a) \( \left(x^{4}\right)^{5} = x^{20} \) b) \( \left(3 x^{2}\right)^{3} = 27x^{6} \) c) \( 4(57 a b)^{0} = 4 \) (since any non-zero number raised to the power of 0 is 1) d) \( \left(\frac{y^{11}}{y^{3}}\right)^{2} = y^{16} \) So the final simplified expressions are: - a) \( x^{20} \) - b) \( 27x^{6} \) - c) \( 4 \) - d) \( y^{16} \)

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For part a, you can simplify \((x^{4})^{5}\) by using the power of a power rule, which states that \((a^{m})^{n} = a^{m \cdot n}\). Therefore, \((x^{4})^{5} = x^{20}\). In part b, \((3x^{2})^{3}\) can be simplified by distributing the exponent to both the constant and the variable. So you get \((3^{3})(x^{2})^{3} = 27x^{6}\). For part c, \(4(57ab)^{0}\) can be simplified using the property that anything raised to the zero power (except zero itself) equals one. This means \((57ab)^{0} = 1\), thus \(4(1) = 4\). In part d, \(\left(\frac{y^{11}}{y^{3}}\right)^{2}\) simplifies to \(\left(y^{11 - 3}\right)^{2} = \left(y^{8}\right)^{2} = y^{16}\).

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