1. Find the value of: \( \begin{array}{ll}\text { (a) } 3^{5} \times 3^{5} & \text { (b) } 9^{4} \times \frac{1}{9^{3}}\end{array} \)
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To solve these expressions, let's break them down step by step. For part (a), we have: \( 3^{5} \times 3^{5} \). According to the rules of exponents, when multiplying the same base, you add the exponents. Thus: \[ 3^{5} \times 3^{5} = 3^{5+5} = 3^{10}. \] Now, calculating \( 3^{10} \): \[ 3^{10} = 59049. \] So, the value for part (a) is \( 59049 \). For part (b), we have: \( 9^{4} \times \frac{1}{9^{3}} \). The fraction can be rewritten with a negative exponent: \[ \frac{1}{9^{3}} = 9^{-3}. \] Thus, we can rewrite the expression as: \[ 9^{4} \times 9^{-3}. \] Again applying the exponent rule for multiplication: \[ 9^{4} \times 9^{-3} = 9^{4-3} = 9^{1}. \] Calculating \( 9^{1} \) gives \( 9 \). Therefore, the value for part (b) is \( 9 \). Final answers: (a) \( 59049 \) and (b) \( 9 \).