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Tell whether each addition problem has a su greater than \( \frac{1}{2} \) a. \( \frac{4}{10}+\frac{9}{100} \) b. \( \frac{1}{100}+\frac{5}{10} \) c. \( \frac{45}{100}+\frac{1}{10} \) d. \( \frac{25}{100}+\frac{3}{10} \) e. \( \frac{3}{10}+\frac{15}{100} \)

Ask by Munoz Collins. in the United States
Mar 12,2025

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Answer

a. Not greater than \( \frac{1}{2} \) b. Greater than \( \frac{1}{2} \) c. Greater than \( \frac{1}{2} \) d. Greater than \( \frac{1}{2} \) e. Not greater than \( \frac{1}{2} \)

Solution

To determine whether each addition problem has a sum greater than \( \frac{1}{2} \), we will first convert \( \frac{1}{2} \) into a fraction with a common denominator for easier comparison. The fraction \( \frac{1}{2} \) is equivalent to \( \frac{50}{100} \). Now, let's evaluate each addition problem step by step: ### a. \( \frac{4}{10} + \frac{9}{100} \) 1. Convert \( \frac{4}{10} \) to a fraction with a denominator of 100: \[ \frac{4}{10} = \frac{40}{100} \] 2. Now add: \[ \frac{40}{100} + \frac{9}{100} = \frac{49}{100} \] 3. Compare \( \frac{49}{100} \) with \( \frac{50}{100} \): \[ \frac{49}{100} < \frac{50}{100} \] **Result:** Not greater than \( \frac{1}{2} \). ### b. \( \frac{1}{100} + \frac{5}{10} \) 1. Convert \( \frac{5}{10} \) to a fraction with a denominator of 100: \[ \frac{5}{10} = \frac{50}{100} \] 2. Now add: \[ \frac{1}{100} + \frac{50}{100} = \frac{51}{100} \] 3. Compare \( \frac{51}{100} \) with \( \frac{50}{100} \): \[ \frac{51}{100} > \frac{50}{100} \] **Result:** Greater than \( \frac{1}{2} \). ### c. \( \frac{45}{100} + \frac{1}{10} \) 1. Convert \( \frac{1}{10} \) to a fraction with a denominator of 100: \[ \frac{1}{10} = \frac{10}{100} \] 2. Now add: \[ \frac{45}{100} + \frac{10}{100} = \frac{55}{100} \] 3. Compare \( \frac{55}{100} \) with \( \frac{50}{100} \): \[ \frac{55}{100} > \frac{50}{100} \] **Result:** Greater than \( \frac{1}{2} \). ### d. \( \frac{25}{100} + \frac{3}{10} \) 1. Convert \( \frac{3}{10} \) to a fraction with a denominator of 100: \[ \frac{3}{10} = \frac{30}{100} \] 2. Now add: \[ \frac{25}{100} + \frac{30}{100} = \frac{55}{100} \] 3. Compare \( \frac{55}{100} \) with \( \frac{50}{100} \): \[ \frac{55}{100} > \frac{50}{100} \] **Result:** Greater than \( \frac{1}{2} \). ### e. \( \frac{3}{10} + \frac{15}{100} \) 1. Convert \( \frac{3}{10} \) to a fraction with a denominator of 100: \[ \frac{3}{10} = \frac{30}{100} \] 2. Now add: \[ \frac{30}{100} + \frac{15}{100} = \frac{45}{100} \] 3. Compare \( \frac{45}{100} \) with \( \frac{50}{100} \): \[ \frac{45}{100} < \frac{50}{100} \] **Result:** Not greater than \( \frac{1}{2} \). ### Summary of Results: - a. Not greater than \( \frac{1}{2} \) - b. Greater than \( \frac{1}{2} \) - c. Greater than \( \frac{1}{2} \) - d. Greater than \( \frac{1}{2} \) - e. Not greater than \( \frac{1}{2} \)

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Let's check each addition problem to see if their sums are greater than \( \frac{1}{2} \) (or \( \frac{50}{100} \)). a. \( \frac{4}{10} + \frac{9}{100} = \frac{40}{100} + \frac{9}{100} = \frac{49}{100} \) (not greater than \( \frac{1}{2} \)) b. \( \frac{1}{100} + \frac{5}{10} = \frac{1}{100} + \frac{50}{100} = \frac{51}{100} \) (greater than \( \frac{1}{2} \)) c. \( \frac{45}{100} + \frac{1}{10} = \frac{45}{100} + \frac{10}{100} = \frac{55}{100} \) (greater than \( \frac{1}{2} \)) d. \( \frac{25}{100} + \frac{3}{10} = \frac{25}{100} + \frac{30}{100} = \frac{55}{100} \) (greater than \( \frac{1}{2} \)) e. \( \frac{3}{10} + \frac{15}{100} = \frac{30}{100} + \frac{15}{100} = \frac{45}{100} \) (not greater than \( \frac{1}{2} \)) In summary, the sums greater than \( \frac{1}{2} \) are: - b: yes - c: yes - d: yes While a and e are not greater than \( \frac{1}{2} \).

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