Question

7. \( 27 a^{3}-1 \)

Ask by Fuentes George. in South Africa
Feb 21,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

\( 27a^{3} - 1 = (3a - 1)(9a^{2} + 3a + 1) \)

Solution

Factor the expression by following steps: - step0: Factor: \(27a^{3}-1\) - step1: Rewrite the expression: \(\left(3a\right)^{3}-1^{3}\) - step2: Factor the expression: \(\left(3a-1\right)\left(\left(3a\right)^{2}+3a\times 1+1^{2}\right)\) - step3: Evaluate: \(\left(3a-1\right)\left(9a^{2}+3a+1\right)\) The expression \( 27 a^{3} - 1 \) can be factored as follows: \[ 27 a^{3} - 1 = (3a - 1)(9a^{2} + 3a + 1) \] So, the factored form is \( (3a - 1)(9a^{2} + 3a + 1) \).

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Mind Expander

Did you know that \( 27a^3 - 1 \) is a special case known as a difference of cubes? You can factor it using the formula \( x^3 - y^3 = (x - y)(x^2 + xy + y^2) \). Here, \( x = 3a \) and \( y = 1 \), which gives us \( (3a - 1)(9a^2 + 3a + 1) \). It's a neat mathematical trick that simplifies calculations and helps in graphing functions! To solve problems involving expressions like \( 27a^3 - 1 \), be cautious about common mistakes. A frequent error is attempting to factor it as a simple binomial without recognizing it's a difference of cubes. Also, be mindful of the signs in your factorization; they can lead to the wrong answer if overlooked. Always double-check your work by expanding your factors to ensure you return to the original expression!

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