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Identify the values of \( a, b \), and \( c \) that cou \[ x^{2}=6(x-3) \] Part 1 of 3 Part 2 of 3 Part 3 of 3

Ask by Savage Wang. in the United States
Feb 25,2025

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Answer

\( a = 1 \), \( b = -6 \), and \( c = 18 \).

Solution

To identify the values of \( a \), \( b \), and \( c \) in the equation \( x^{2} = 6(x - 3) \), we will first rearrange the equation into standard quadratic form \( ax^2 + bx + c = 0 \). ### Step 1: Rearranging the Equation Starting with the given equation: \[ x^{2} = 6(x - 3) \] We can expand the right side: \[ x^{2} = 6x - 18 \] Next, we will move all terms to one side of the equation: \[ x^{2} - 6x + 18 = 0 \] ### Step 2: Identifying \( a \), \( b \), and \( c \) Now, we can identify the coefficients \( a \), \( b \), and \( c \) from the standard form \( ax^2 + bx + c = 0 \): - \( a = 1 \) (coefficient of \( x^2 \)) - \( b = -6 \) (coefficient of \( x \)) - \( c = 18 \) (constant term) ### Final Values Thus, the values are: - \( a = 1 \) - \( b = -6 \) - \( c = 18 \)

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First, let's rewrite the equation \( x^{2} = 6(x - 3) \) so that it is in standard form. Expanding the right side gives us: \[ x^{2} = 6x - 18. \] Now, we can bring all terms to one side to set the equation to zero: \[ x^{2} - 6x + 18 = 0. \] In this format, we can identify the values of \( a \), \( b \), and \( c \): - \( a = 1 \) - \( b = -6 \) - \( c = 18 \) So the identified values are: \( a = 1 \), \( b = -6 \), \( c = 18 \).

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