Question
Work out the smallest integer value that \( x \) could take if \[ 6 x+3 \geq 27 \]
Ask by Todd Mullins. in the United Kingdom
Mar 08,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The smallest integer value for \( x \) is 4.
Solution
1. Start with the inequality:
\[
6x + 3 \geq 27
\]
2. Subtract \(3\) from both sides:
\[
6x \geq 27 - 3 \quad \Rightarrow \quad 6x \geq 24
\]
3. Divide both sides by \(6\):
\[
x \geq \frac{24}{6} \quad \Rightarrow \quad x \geq 4
\]
4. Since \( x \) must be an integer, the smallest integer value that \( x \) can take is:
\[
x = 4
\]
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Simplify this solution Mind Expander
To solve the inequality \( 6x + 3 \geq 27 \), we first isolate \( x \). Start by subtracting 3 from both sides: \[ 6x \geq 27 - 3 \] This simplifies to: \[ 6x \geq 24 \] Next, we divide both sides by 6: \[ x \geq 4 \] The smallest integer value that \( x \) could take is \( 4 \).
