Question
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1.1. \( \frac{33}{6}+\left(-\frac{11}{2}\right) \)

Ask by Olson Estrada. in Portugal
Mar 11,2025

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Tutor-Verified Answer

Answer

A soma \( \frac{33}{6} + \left(-\frac{11}{2}\right) \) é igual a \( 0 \).

Solution

Calculate the value by following steps: - step0: Calculate: \(\frac{33}{6}+\left(-\frac{11}{2}\right)\) - step1: Remove the parentheses: \(\frac{33}{6}-\frac{11}{2}\) - step2: Reduce the fraction: \(\frac{11}{2}-\frac{11}{2}\) - step3: Subtract the numbers: \(0\) A soma \( \frac{33}{6} + \left(-\frac{11}{2}\right) \) resulta em \( 0 \). Aqui está a explicação passo a passo: 1. Primeiro, convertemos \( \frac{11}{2} \) para ter o mesmo denominador que \( \frac{33}{6} \). O denominador comum é 6. 2. Para isso, multiplicamos \( \frac{11}{2} \) por \( \frac{3}{3} \), resultando em \( \frac{33}{6} \). 3. Agora, temos \( \frac{33}{6} + \left(-\frac{33}{6}\right) \). 4. A soma de \( \frac{33}{6} \) e \( -\frac{33}{6} \) é \( 0 \). Portanto, a resposta final é \( 0 \).

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The Deep Dive

To simplify \( \frac{33}{6}+\left(-\frac{11}{2}\right) \), first convert \( \frac{33}{6} \) to a simpler form: \[ \frac{33}{6} = \frac{11}{2} \] Now, you can substitute this into the original expression: \[ \frac{11}{2} + \left(-\frac{11}{2}\right) = \frac{11}{2} - \frac{11}{2} = 0 \] Thus, the final result is \( 0 \).

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