What is the quotient? \( \frac{n+3}{2 n-6}+\frac{n+3}{3 n-9} \) \( \frac{2}{3} \) \( \frac{3}{2} \) \( \frac{(n+3)^{2}}{6(n-3)^{2}} \) \( 0 \frac{6(n-3)^{2}}{(n+3)^{2}} \)
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To solve the expression \( \frac{n+3}{2n-6}+\frac{n+3}{3n-9} \), we first rewrite the denominators. Notice that \( 2n-6 \) and \( 3n-9 \) can be factored: \( 2(n-3) \) and \( 3(n-3) \) respectively. This helps in finding a common denominator of \( 6(n-3) \). We can combine the fractions into a single expression, which leads us to: \[ \frac{(n+3)(3) + (n+3)(2)}{6(n-3)} = \frac{(n+3)(5)}{6(n-3)} = \frac{5(n+3)}{6(n-3)}. \] Thus, the correct form simplifies to \( \frac{5(n+3)}{6(n-3)} \). For the next steps, remember common mistakes: make sure to factor and simplify where possible! It's easy to overlook negative signs or factor out incorrect terms. And if you're unsure about your final answer, plug in some values for \( n \) to verify your quotient is consistent across the board.