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What is the mass of an object that creates 33,650 joules of energy by traveling at 43 m/s? (Round to one decimal place) \[ \]

Ask by Joseph Adkins. in the United States
Feb 28,2025

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Answer

The mass of the object is approximately 36.4 kg.

Solution

We start with the kinetic energy formula:   KE = (1/2) m v² Given:   KE = 33,650 joules   v = 43 m/s Solve for m:   m = (2 × KE) / v² Plug in the values:   m = (2 × 33,650) / (43²)   m = 67,300 / 1,849 Calculate:   m ≈ 36.4 kg Thus, the mass of the object is approximately 36.4 kg.

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To find the mass of the object, you can use the kinetic energy formula: \[ KE = \frac{1}{2} mv^2 \] Rearranging this gives: \[ m = \frac{2 \cdot KE}{v^2} \] Substituting in the values: \[ m = \frac{2 \cdot 33,650 \, \text{J}}{(43 \, \text{m/s})^2} = \frac{67,300}{1849} \approx 36.4 \, \text{kg} \] So, the mass of the object is approximately 36.4 kg. Understanding how kinetic energy works is like learning about the relationship between a car's speed and how much fuel it uses on a road trip—higher speeds require more energy, mimicking how powerful engines drive those amazing sports cars! When working with formulas, a common mistake is misplacing the square or missing the half in the kinetic energy formula. Always double-check your algebra—adding a little bit of caution can lead to smoother calculations, just like safely navigating a busy intersection!

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