19. A mechanic used a hydraulic lift to raise a $$ 12,054 \mathrm{~N} $$ car 1.89 m above the floor of a garage. It took 4.75 s to raise the car. What was the power output of the lift? Type a response 20. How much work is done using a 500-watt microwave oven for 5 minutes? Type a response 20 Hen

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**Problem 19**

1. The work done to lift the car is given by  
   $$
   W = F \times d
   $$
   where  
   $$ F = 12\,054 \, \mathrm{N} $$ (force) and  
   $$ d = 1.89 \, \mathrm{m} $$ (distance).  
   Thus,  
   $$
   W = 12\,054 \times 1.89 \approx 22\,782.06 \, \mathrm{J}
   $$

2. The power output is the work done per unit time:  
   $$
   P = \frac{W}{t}
   $$
   Given $$ t = 4.75 \, \mathrm{s} $$, we have  
   $$
   P = \frac{22\,782.06}{4.75} \approx 4\,796.22 \, \mathrm{W}
   $$
   Rounding to an appropriate number of significant figures, the power output is about  
   $$
   P \approx 4.80 \times 10^3 \, \mathrm{W}
   $$

---

**Problem 20**

1. The work done (or energy used) with a microwave oven is calculated using  
   $$
   W = P \times t
   $$
   where  
   $$ P = 500 \, \mathrm{W} $$ and  
   $$ t = 5 \, \mathrm{minutes} $$.  
   First, convert the time into seconds:  
   $$
   t = 5 \times 60 = 300 \, \mathrm{s}
   $$

2. Now calculate the work:  
   $$
   W = 500 \times 300 = 150\,000 \, \mathrm{J}
   $$

---

**Answers**

- The power output of the lift is approximately $$ 4.80 \times 10^3 \, \mathrm{W} $$.
- The work done by the 500-watt microwave oven in 5 minutes is $$ 150\,000 \, \mathrm{J} $$.
**Problem 19** - The power output of the lift is approximately 4,800 watts. **Problem 20** - The work done by the microwave oven in 5 minutes is 150,000 joules.

19. A mechanic used a hydraulic lift to raise a \( 12,054 \mathrm{~N} \) car 1.89 m above the floor of a garage. It took 4.75 s to raise the car. What was the power output of the lift? Type a response 20. How much work is done using a 500-watt microwave oven for 5 minutes? Type a response 20 Hen

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