Add or subtract. \( 2 \sqrt{27}-2 \sqrt{18}+\sqrt{75} \) \( 2 \sqrt{27}-2 \sqrt{18}+\sqrt{75}=\square \) (Simplify your answer. Type an exact answer, using radicals as needed.)

To simplify the expression \( 2 \sqrt{27} - 2 \sqrt{18} + \sqrt{75} \), we will first break down each square root: 1. \( \sqrt{27} = \sqrt{9 \cdot 3} = 3\sqrt{3} \) Hence, \( 2\sqrt{27} = 2 \cdot 3\sqrt{3} = 6\sqrt{3} \). 2. \( \sqrt{18} = \sqrt{9 \cdot 2} = 3\sqrt{2} \) Therefore, \( -2\sqrt{18} = -2 \cdot 3\sqrt{2} = -6\sqrt{2} \). 3. \( \sqrt{75} = \sqrt{25 \cdot 3} = 5\sqrt{3} \). Now, we combine all parts: \[ 2 \sqrt{27} - 2 \sqrt{18} + \sqrt{75} = 6\sqrt{3} - 6\sqrt{2} + 5\sqrt{3} \] Combine like terms: \[ (6\sqrt{3} + 5\sqrt{3}) - 6\sqrt{2} = 11\sqrt{3} - 6\sqrt{2} \] Thus, the simplified expression is: \[ \boxed{11\sqrt{3} - 6\sqrt{2}} \]