Use properties of logarithms to condense the logarithmic expression. Write the expression as a single logarithm whose coefficient is 1. Where possible, evaluate logarithmic expressions. \( \log 125+\log 8 \) \( \log 125+\log 8=\square \) (Simplify your answer.)

To condense the logarithmic expression, you can use the property that states \(\log a + \log b = \log(ab)\). Therefore, we combine the two logarithms: \[ \log 125 + \log 8 = \log(125 \cdot 8) \] Now, calculate \(125 \cdot 8\): \[ 125 \cdot 8 = 1000 \] Thus, we have: \[ \log 125 + \log 8 = \log 1000 \] Since \(1000 = 10^3\), you can further simplify this: \[ \log 1000 = \log(10^3) = 3 \] So the final answer is: \[ \log 125 + \log 8 = \log 1000 = 3 \] Therefore, \[ \log 125+\log 8=3 \]