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How many grams of barium chloride are needed to make 100. grams of barium sulfate?

Ask by Cummings Thornton. in the United States
Mar 11,2025

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Approximately 89.3 grams of barium chloride are needed to make 100 grams of barium sulfate.

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The Deep Dive

To find out how many grams of barium chloride (BaCl₂) are needed to produce 100 grams of barium sulfate (BaSO₄), we first need to look at the balanced chemical reaction:
From the reaction, we see that 1 mole of barium chloride produces 1 mole of barium sulfate. The molar masses are approximately:
  • BaCl₂: 137.33 (Ba) + 2 × 35.45 (Cl) = 207.23 g/mol
  • BaSO₄: 137.33 (Ba) + 32.07 (S) + 4 × 16.00 (O) = 233.39 g/mol
Now, we can find out how many moles of barium sulfate correspond to 100 grams:
Using the stoichiometry from the balanced equation (1:1 ratio), we also need 0.428 moles of BaCl₂ to produce this amount of BaSO₄. Now calculate the mass of BaCl₂:
Rounding this, we can say that approximately 89.3 grams of barium chloride are needed to produce 100 grams of barium sulfate.
So the answer is:
89.3 g

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