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Can D'Angelo build a tower at least \( 4^{\prime \prime} \) tall by stacking three \( 1 \frac{1}{2} \) " blocks?

Ask by Wood Burton. in the United States
Mar 21,2025

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Answer

D'Angelo can build a tower at least \(4^{\prime \prime}\) tall by stacking three \(1 \frac{1}{2} \) " blocks.

Solution

1. Each block has a height of \(1 \frac{1}{2} = \frac{3}{2}\) inches. 2. The total height when stacking three blocks is: \[ 3 \times \frac{3}{2} = \frac{9}{2} = 4.5 \text{ inches}. \] 3. Since \(4.5\) inches is greater than \(4\) inches, D'Angelo can indeed build a tower that is at least \(4^{\prime \prime}\) tall.

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To determine if D'Angelo can build a tower at least \( 4^{\prime \prime} \) tall by stacking three \( 1 \frac{1}{2} \) " blocks, we first need to calculate the height of the three blocks stacked together. Each block has a height of \( 1 \frac{1}{2} \) inches, which can be expressed as: \[ 1 \frac{1}{2} = \frac{3}{2} \text{ inches} \] Now, if D'Angelo stacks three blocks, the total height \( H \) can be calculated as: \[ H = 3 \times \frac{3}{2} \] Calculating this gives: \[ H = \frac{9}{2} \text{ inches} \] To convert \( \frac{9}{2} \) to a decimal, we perform the division: \[ \frac{9}{2} = 4.5 \text{ inches} \] Since \( 4.5 \) inches is greater than \( 4 \) inches, D'Angelo can indeed build a tower at least \( 4^{\prime \prime} \) tall. So, yes, D'Angelo can build a tower that is at least \( 4^{\prime \prime} \) tall by stacking the three blocks.

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