BCAL-WORE CONNECTION The diagram shows the plans for the triangular park. How much longer is \( B C \) than \( A C \) ? \( \left(3 x^{2}-25 x-12\right) \) feet \( \left(3 x^{2}-5 x-12\right) \) feet \( \left(3 x^{2}+5 x-4\right) \) feet \( \left(3 x^{2}+25 x-4\right) \) feet DONE
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Beyond the Answer
To find how much longer \( BC \) is than \( AC \), we need to subtract the expression for \( AC \) from the expression for \( BC \). This means we'll take: \[ BC - AC = (3x^2 - 25x - 12) - (3x^2 - 5x - 12) \] When you simplify this, you’ll find that the \( 3x^2 \) terms cancel, leaving you with: \[ -25x - 12 + 5x + 12 = -20x \] So, \( BC \) is \( 20x \) feet longer than \( AC \)! What a neat little mystery we solved here! One of the best ways to improve your skills in algebraic expressions is by practicing problems involving simplification and subtraction, as you now know how to derive dimensions through expressions. If you're tackling different variables, just remember to keep your terms organized to uncover the values quicker!