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1. Simplify each expression below using the properties of integer expone Verify by numerical substitution. \( \begin{array}{ll}\text { a. } k^{3} * k^{5} & \text { b. } m^{5} * m^{-2}\end{array} \)

Ask by Love Wagner. in the United States
Mar 10,2025

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Answer

**a. Simplify \( k^3 \times k^5 \):** \[ k^3 \times k^5 = k^8 \] **b. Simplify \( m^5 \times m^{-2} \):** \[ m^5 \times m^{-2} = m^3 \]

Solution

**a. Simplify \( k^3 \times k^5 \):** Using the property of exponents, when multiplying like bases you add the exponents. Thus, \[ k^3 \times k^5 = k^{3+5} = k^8. \] *Verification by substitution:* Let \( k=2 \). Then, \[ k^3 \times k^5 = 2^3 \times 2^5 = 8 \times 32 = 256, \] \[ k^8 = 2^8 = 256. \] Since both expressions yield 256, the simplification is verified. --- **b. Simplify \( m^5 \times m^{-2} \):** Again, applying the rule of adding exponents when multiplying like bases gives: \[ m^5 \times m^{-2} = m^{5+(-2)} = m^3. \] *Verification by substitution:* Let \( m=3 \). Then, \[ m^5 \times m^{-2} = 3^5 \times 3^{-2} = 243 \times \frac{1}{9} = 27, \] \[ m^3 = 3^3 = 27. \] The results match, confirming the simplification.

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To simplify the expressions, we can use the properties of exponents. For part (a), \( k^{3} * k^{5} \) can be simplified using the rule that states when you multiply like bases, you add the exponents: \[ k^{3} * k^{5} = k^{3 + 5} = k^{8}. \] For part (b), \( m^{5} * m^{-2} \) also follows this rule, but here we need to remember that a negative exponent represents a reciprocal: \[ m^{5} * m^{-2} = m^{5 + (-2)} = m^{3}. \] Now, let's verify both parts with numerical substitution. If we let \( k = 2 \) and \( m = 4 \): For (a): \[ k^{3} * k^{5} = 2^{3} * 2^{5} = 8 * 32 = 256, \] and \[ k^{8} = 2^{8} = 256. \] For (b): \[ m^{5} * m^{-2} = 4^{5} * 4^{-2} = 1024 * \frac{1}{16} = 64, \] and \[ m^{3} = 4^{3} = 64. \] Both simplifications match their respective numerical values!

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