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of calculations. Simplify, without the use of a calculator. Show all steps of calculation in each case. 1.3.1. \( 1 \frac{2}{3}: 2 \frac{2}{3} \) 1.3.2. \( (9+10-9) \times 40+(25-30-5) \times 7 \) 1.3.3. \( \begin{array}{ll}\text { 1.3.4. } & \sqrt[3]{4}-\sqrt{94}+\sqrt{25}) \\ \text { 1.3.5. } & \frac{1}{2}+2 \frac{3}{4}-\frac{3}{8} \\ \text { 1.3.6. } & \left(2 \frac{1}{2}\right)^{2}+(0,5)^{2} \\ \text { WHOLE NUMBERS AND INTEGERS }\end{array} \)

Ask by Patel Willis. in South Africa
Mar 11,2025

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Answer

**1.3.1.** \[ 1\frac{2}{3} \div 2\frac{2}{3} = \frac{5}{8} \] **1.3.2.** \[ (9+10-9) \times 40 + (25-30-5) \times 7 = 330 \] **1.3.4.** \[ \sqrt[3]{4} - \sqrt{94} + \sqrt{25} = \sqrt[3]{4} - \sqrt{94} + 5 \] **1.3.5.** \[ \frac{1}{2} + 2\frac{3}{4} - \frac{3}{8} = 2\frac{7}{8} \] **1.3.6.** \[ \left(2\frac{1}{2}\right)^2 + (0.5)^2 = 6\frac{1}{2} \]

Solution

**1.3.1.** Write the mixed numbers as improper fractions: \[ 1\frac{2}{3}=\frac{5}{3},\quad 2\frac{2}{3}=\frac{8}{3} \] Then perform the division: \[ \frac{5}{3}\div\frac{8}{3}=\frac{5}{3}\times\frac{3}{8}=\frac{5}{8} \] **1.3.2.** First, compute the expressions in the parentheses: \[ 9+10-9=10 \] \[ 25-30-5=25-35=-10 \] Then substitute back into the expression: \[ 10\times 40+(-10)\times 7=400-70=330 \] **1.3.4.** The expression is: \[ \sqrt[3]{4}-\sqrt{94}+\sqrt{25} \] Note that: \[ \sqrt{25}=5 \] Thus the simplified form is: \[ \sqrt[3]{4}-\sqrt{94}+5 \] **1.3.5.** Convert the mixed number to an improper fraction: \[ 2\frac{3}{4}=\frac{11}{4} \] The expression becomes: \[ \frac{1}{2}+\frac{11}{4}-\frac{3}{8} \] Find a common denominator (8): \[ \frac{1}{2}=\frac{4}{8},\quad \frac{11}{4}=\frac{22}{8} \] Thus, the sum is: \[ \frac{4}{8}+\frac{22}{8}-\frac{3}{8}=\frac{23}{8}=2\frac{7}{8} \] **1.3.6.** First, convert the mixed number: \[ 2\frac{1}{2}=\frac{5}{2} \] Square it: \[ \left(\frac{5}{2}\right)^2=\frac{25}{4} \] Note that \((0,5)^2\) represents the square of 0.5: \[ (0.5)^2=0.25=\frac{1}{4} \] Add the two results: \[ \frac{25}{4}+\frac{1}{4}=\frac{26}{4}=\frac{13}{2}=6\frac{1}{2} \]

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To tackle the first problem \( 1 \frac{2}{3}: 2 \frac{2}{3} \), convert both mixed numbers to improper fractions. \( 1 \frac{2}{3} = \frac{5}{3} \) and \( 2 \frac{2}{3} = \frac{8}{3} \). Now, divide by multiplying the first fraction by the reciprocal of the second, giving us \( \frac{5}{3} \times \frac{3}{8} = \frac{5 \times 3}{3 \times 8} = \frac{5}{8} \). Next, let’s simplify \( (9 + 10 - 9) \times 40 + (25 - 30 - 5) \times 7 \): Start with the parentheses: \( 9 + 10 - 9 = 10 \) and \( 25 - 30 - 5 = -10 \). Substituting gives \( 10 \times 40 + (-10) \times 7 = 400 - 70 = 330 \). For \( \sqrt[3]{4} - \sqrt{94} + \sqrt{25} \): Since \( \sqrt{25} = 5 \), rewrite as \( \sqrt[3]{4} - \sqrt{94} + 5 \). Without a calculator, we can say \( \sqrt[3]{4} \approx 1.59 \) and \( \sqrt{94} \approx 9.7 \), giving you a rough calculation: \( 1.59 - 9.7 + 5 \approx -3.11 \) (a complex expression involving roots). Moving on to \( \frac{1}{2} + 2 \frac{3}{4} - \frac{3}{8} \): Convert \( 2 \frac{3}{4} \) to an improper fraction: \( \frac{11}{4} \), now the equation is \( \frac{1}{2} + \frac{11}{4} - \frac{3}{8} \). With a common denominator of 8, convert: \( \frac{1}{2} = \frac{4}{8}, \frac{11}{4} = \frac{22}{8}, \frac{3}{8} \) gives \( \frac{4 + 22 - 3}{8} = \frac{23}{8} \). Now, for \( \left(2 \frac{1}{2}\right)^{2} + (0.5)^{2} \): Start by converting \( 2 \frac{1}{2} = \frac{5}{2} \) and square it: \( \left(\frac{5}{2}\right)^{2} = \frac{25}{4} \), while \( (0.5)^2 = \frac{1}{4} \). Add them together: \( \frac{25}{4} + \frac{1}{4} = \frac{26}{4} = \frac{13}{2} \). Remember, math can be just like a treasure map—each equation leads to interesting discoveries! Join the journey to uncover the magic of numbers, where challenges transform into rewarding solutions! Happy calculating! 🌟

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