Question
A probability experiment consists of rolling a fair 10 -sided die, numbered 1 to 10 . Find the probability of the event below. rolling a number greater than 7 The probability is \( \square \). (Type an integer or decimal rounded to three decimal places as needed.)
Ask by Lee Rodriguez. in the United States
Feb 25,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The probability is 0.300.
Solution
There are 3 outcomes greater than 7 (namely, 8, 9, and 10) out of the 10 possible outcomes. Therefore, the probability is 3/10 = 0.3, which rounds to 0.300.
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Extra Insights
When rolling a fair 10-sided die, the numbers greater than 7 are 8, 9, and 10. That's a total of 3 favorable outcomes. Since the die has 10 sides, the total number of outcomes is 10. Therefore, the probability of rolling a number greater than 7 is calculated as follows: \[ P(\text{number > 7}) = \frac{\text{number of favorable outcomes}}{\text{total outcomes}} = \frac{3}{10} = 0.300 \] The probability is \( 0.300 \).