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A probability experiment consists of rolling a fair 10 -sided die, numbered 1 to 10 . Find the probability of the event below. rolling a number greater than 7 The probability is \( \square \). (Type an integer or decimal rounded to three decimal places as needed.)

Ask by Lee Rodriguez. in the United States
Feb 25,2025

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The probability is 0.300.

Solution

There are 3 outcomes greater than 7 (namely, 8, 9, and 10) out of the 10 possible outcomes. Therefore, the probability is 3/10 = 0.3, which rounds to 0.300.

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When rolling a fair 10-sided die, the numbers greater than 7 are 8, 9, and 10. That's a total of 3 favorable outcomes. Since the die has 10 sides, the total number of outcomes is 10. Therefore, the probability of rolling a number greater than 7 is calculated as follows: \[ P(\text{number > 7}) = \frac{\text{number of favorable outcomes}}{\text{total outcomes}} = \frac{3}{10} = 0.300 \] The probability is \( 0.300 \).

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