Question
4. Using algebraic rules, find the value of \( k \) for which \( 58^{2}-46^{2}=12 k \) \[ \begin{aligned} 58^{2} & =60^{2}-2^{2} \\ & =3600-4 \\ & =3596\end{aligned} \]
Ask by Garza Sherman. in Singapore
Mar 09,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
\( k = 104 \)
Solution
We can simplify the expression \(58^{2}-46^{2}\) by using the difference of squares formula:
\[
a^{2}-b^{2}=(a-b)(a+b)
\]
Let \(a=58\) and \(b=46\). Then:
\[
58^{2}-46^{2} = (58-46)(58+46)
\]
Calculate the differences and sums:
\[
58-46 = 12 \quad \text{and} \quad 58+46 = 104
\]
Substitute these back into the expression:
\[
58^{2}-46^{2} = 12 \times 104 = 1248
\]
We are given that:
\[
58^{2}-46^{2}=12k
\]
Thus, equate:
\[
12k = 1248
\]
Solve for \(k\) by dividing both sides by 12:
\[
k=\frac{1248}{12}=104
\]
So, the value of \(k\) is \(\boxed{104}\).
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Mind Expander
Let's start by simplifying \( 58^{2} - 46^{2} \) using the difference of squares formula, which states that \( a^{2} - b^{2} = (a - b)(a + b) \). Here, \( a = 58 \) and \( b = 46 \). Calculating: \[ 58^{2} - 46^{2} = (58 - 46)(58 + 46) = 12 \times 104 = 1248. \] Now we have: \[ 1248 = 12k. \] To solve for \( k \), divide both sides by 12: \[ k = \frac{1248}{12} = 104. \] Therefore, the value of \( k \) is \( 104 \).